Oracle中行列转换及pivot子句怎么用

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一、11g以前的行列转换方法

创建测试表：

create table emp_phone(name varchar2(50), type char, phone varchar2(50));

insert into emp_phone values(张三, 1, 1234-5678);

insert into emp_phone values(张三, 2, 3219-6066);

insert into emp_phone values(张三, 3, 5365-9583);

insert into emp_phone values(李四, 1, 6837-2745);

insert into emp_phone values(李四, 3, 2649-5820);

insert into emp_phone values(王五, 1, 5838-9002);

insert into emp_phone values(王五, 2, 2749-5580);

insert into emp_phone values(陈六, 2, 9876-3453);

commit;

select * from emp_phone;

NAME                 T PHONE

-------------------- - --------------------

张三                 1 1234-5678

张三                 2 3219-6066

张三                 3 5365-9583

李四                 1 6837-2745

李四                 3 2649-5820

王五                 1 5838-9002

王五                 2 2749-5580

陈六                 2 9876-3453

列转行：

select name, max(decode(type, 1, phone)) home, max(decode(type, 2, phone)) office, max(decode(type, 3, phone)) mobile from emp_phone group by name;

NAME                 HOME                 OFFICE               MOBILE

-------------------- -------------------- -------------------- --------------------

陈六                                      9876-3453

王五                 5838-9002            2749-5580

李四                 6837-2745                                 2649-5820

张三                 1234-5678            3219-6066            5365-9583

行转回列：

create table emp_phone1 as

(select name, max(decode(type, 1, phone)) home, max(decode(type, 2, phone)) office, max(decode(type, 3, phone)) mobile from emp_phone group by name);

select * from emp_phone1;

NAME                 HOME                 OFFICE               MOBILE

-------------------- -------------------- -------------------- --------------------

陈六                                      9876-3453

王五                 5838-9002            2749-5580

李四                 6837-2745                                 2649-5820

张三                 1234-5678            3219-6066            5365-9583

select name, decode(lvl, 1, home, 2, office, 3, mobile) phone

  from emp_phone1, (select level lvl from dual connect by level <= 3)

where decode(lvl, 1, home, 2, office, 3, mobile) is not null

 order by name;

NAME                 PHONE

-------------------- --------------------

陈六                 9876-3453

李四                 6837-2745

李四                 2649-5820

王五                 2749-5580

王五                 5838-9002

张三                 1234-5678

张三                 5365-9583

张三                 3219-6066

二、11g自带的行列转换

使用pivot和unpivot使得行列转换变的很简单。

列转行：

select * from emp_phone pivot(max(phone) for type in (1 as home, 2 as office, 3 as mobile));

NAME                 HOME                 OFFICE               MOBILE

-------------------- -------------------- -------------------- --------------------

陈六                                      9876-3453

王五                 5838-9002            2749-5580

李四                 6837-2745                                 2649-5820

张三                 1234-5678            3219-6066            5365-9583

行转列：

select * from emp_phone1 unpivot(phone for type in (home as 1, office as 2, mobile as 3));

NAME                       TYPE PHONE

-------------------- ---------- --------------------

陈六                          2 9876-3453

王五                          1 5838-9002

王五                          2 2749-5580

李四                          1 6837-2745

李四                          3 2649-5820

张三                          1 1234-5678

张三                          2 3219-6066

张三                          3 5365-9583

再举一个Oracle示例方案scott中的例子

select * from emp;

     EMPNO ENAME      JOB              MGR HIREDATE                   SAL       COMM     DEPTNO

---------- ---------- --------- ---------- ------------------- ---------- ---------- ----------

7369 SMITH      CLERK           7902 1980-12-17 00:00:00        800                    20

7499 ALLEN      SALESMAN        7698 1981-02-20 00:00:00       1600        300         30

7521 WARD       SALESMAN        7698 1981-02-22 00:00:00       1250        500         30

7566 JONES      MANAGER         7839 1981-04-02 00:00:00       2975                    20

7654 MARTIN     SALESMAN        7698 1981-09-28 00:00:00       1250       1400         30

7698 BLAKE      MANAGER         7839 1981-05-01 00:00:00       2850                    30

7782 CLARK      MANAGER         7839 1981-06-09 00:00:00       2450                    10

      7788 SCOTT      ANALYST         7566 1987-04-19 00:00:00       3000                    20

7839 KING       PRESIDENT            1981-11-17 00:00:00       5000                    10

7844 TURNER     SALESMAN        7698 1981-09-08 00:00:00       1500          0         30

7876 ADAMS      CLERK           7788 1987-05-23 00:00:00       1100                    20

7900 JAMES      CLERK           7698 1981-12-03 00:00:00        950                    30

7902 FORD       ANALYST         7566 1981-12-03 00:00:00       3000                    20

7934 MILLER     CLERK           7782 1982-01-23 00:00:00       1300                    10

列出各部门的工资总和

select * from (select sal, deptno from emp) pivot(sum(sal) for deptno in (10 as dept_10, 20 as dept_20, 30 as dept_30));

   DEPT_10    DEPT_20    DEPT_30

---------- ---------- ----------

      8750      10875       9400

这里deptno是有限的、可穷举的，如果是变化的、随机添加的，则可在in后面使用any或者子查询，此时查询的结果是XML格式串

select *

  from ((select sal, deptno from emp) pivot

        xml(sum(sal) for deptno in (any)));

如果是用子查询

select *

  from ((select sal, deptno from emp) pivot

xml(sum(sal) for deptno in (select deptno from emp where deptno in (10, 20, 30))));

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